Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:31Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
479K
3β² + 6β + 2 = 0
∫₀^∞ e^(-x²) dx = √π / 2
276K
det| 9 4 ; 1 10 | = 86
129K
F = ma
\oint_C \vec{F}\cdot d\vec{r} = 0
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 3 3 ; 4 4 | = 0
153K
1x² + 5x + 7 = 0
det| 3 7 ; 2 4 | = -2
473K
∇²ψ = 0
∫₀^∞ e^(-n²) dn = √π / 2
188K
3φ² + 8φ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}