Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:41Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
6φ² + 8φ + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
63K
∂φ/∂φ = 1φ
\oint_C \vec{F}\cdot d\vec{r} = 0
366K
det| 9 4 ; 1 10 | = 86
201K
det| 4 8 ; 1 5 | = 12
det| 4 8 ; 3 5 | = -4
176K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
∑_{k=1}^{n} k = n(n+1)/2
359K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O