Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 15:50Z
d/dz [z^3] = 3z^2
∑_{k=1}^{n} k = n(n+1)/2
479K
6φ² + 8φ + 0 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
276K
det| 9 4 ; 1 10 | = 86
129K
ω = 2πf
det| 10 4 ; 1 11 | = 106
390K
det| 10 8 ; 7 11 | = 54
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 7 9 ; 1 8 | = 47
153K
det| 5 6 ; 2 6 | = 18