Math Dump /sym/33b119
id=101245 · host=jp.commstar.world · 2026-09-01 21:05Z
∇ × E = −∂B/∂t
det| 4 1 ; 6 5 | = 14
402K
det| 6 5 ; 1 7 | = 37
det| 5 3 ; 7 6 | = 9
398K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∇ × E = −∂B/∂t
7β² + 9β + 3 = 0
det| 5 1 ; 4 6 | = 26
det| 8 1 ; 4 9 | = 68
5r² + 9r + 5 = 0
ΔS ≥ 0
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 10 1 ; 1 11 | = 109
det| 1 5 ; 6 2 | = -28