Math Dump /sym/8c81c7
id=122975 · host=jp.commstar.world · 2026-09-01 21:08Z
∇²ψ = 0
det| 4 1 ; 6 5 | = 14
402K
det| 7 1 ; 0 8 | = 56
det| 5 3 ; 7 6 | = 9
398K
∇ × E = −∂B/∂t
∫₀^∞ e^(-z²) dz = √π / 2
det| 9 1 ; 1 10 | = 89
9φ² + 9φ + 1 = 0
det| 2 6 ; 1 3 | = 0
det| 9 5 ; 1 10 | = 85
6t² + 6t + 4 = 0
6θ² + 6θ + 5 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
iħ ∂ψ/∂t = Ĥψ