Math Dump /sym/cdfe97
id=131942 · host=jp.commstar.world · 2026-09-01 21:08Z
∇²β = 0
det| 4 1 ; 6 5 | = 14
402K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 3 ; 7 6 | = 9
398K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
det| 6 5 ; 4 7 | = 22
8z² + 8z + 1 = 0
8z² + 4z + 3 = 0
7t² + 9t + 4 = 0
6γ² + 2γ + 2 = 0
8r² + 1r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf