Math Dump /sym/8a24c2
id=132795 · host=jp.commstar.world · 2026-09-01 21:16Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 4 1 ; 6 5 | = 14
402K
det| 2 1 ; 0 3 | = 6
det| 5 3 ; 7 6 | = 9
398K
∇²r = 0
N₂ + 3H₂ ⇌ 2NH₃
5ψ² + 9ψ + 0 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 8 8 ; 2 9 | = 56
det| 4 3 ; 5 5 | = 5
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
e^{i\pi} + 1 = 0
\lim_{n\to 0} \frac{\sin n}{n} = 1