Math Dump /sym/191fe4
id=136615 · host=jp.commstar.world · 2026-09-01 21:11Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 4 1 ; 6 5 | = 14
402K
F = ma
det| 5 3 ; 7 6 | = 9
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-ψ²) dψ = √π / 2
N₂ + 3H₂ ⇌ 2NH₃
6α² + 5α + 0 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dω [ω^3] = 3ω^2
iħ ∂ψ/∂t = Ĥψ