Math Dump /sym/bf8324
id=137374 · host=jp.commstar.world · 2026-09-01 21:05Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 1 ; 6 5 | = 14
402K
2ω² + 9ω + 3 = 0
det| 5 3 ; 7 6 | = 9
398K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
E = mc²
4z² + 8z + 4 = 0
det| 6 6 ; 6 7 | = 6
5ω² + 9ω + 0 = 0
12r² + 6r + 7 = 0
E = mc²
iħ ∂ψ/∂t = Ĥψ
det| 7 5 ; 7 8 | = 21
e^{i\pi} + 1 = 0