Math Dump /sym/9ef688
id=138358 · host=jp.commstar.world · 2026-09-01 21:14Z
N₂ + 3H₂ ⇌ 2NH₃
det| 4 1 ; 6 5 | = 14
402K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 5 3 ; 7 6 | = 9
398K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∇ × E = −∂B/∂t
det| 7 8 ; 7 8 | = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
11φ² + 1φ + 3 = 0
det| 12 8 ; 2 13 | = 140
\frac{9}{5} \sum_{i=1}^{n} i^{2}
∂β/∂θ = 1β
PV = nRT