Math Dump /sym/1ff9e7
id=147279 · host=jp.commstar.world · 2026-09-01 21:05Z
1φ² + 1φ + 3 = 0
det| 4 1 ; 6 5 | = 14
402K
E = mc²
det| 5 3 ; 7 6 | = 9
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 5 ; 2 6 | = 20
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
ΔS ≥ 0
E = mc²
ω = 2πf
2H₂ + O₂ → 2H₂O
\frac{5}{6} \sum_{i=1}^{n} i^{2}
12θ² + 4θ + 5 = 0