Math Dump /sym/ef54f9
id=186009 · host=jp.commstar.world · 2026-09-01 21:10Z
∇ × E = −∂B/∂t
det| 4 1 ; 6 5 | = 14
402K
det| 1 1 ; 0 2 | = 2
det| 5 3 ; 7 6 | = 9
398K
CaCO₃ → CaO + CO₂
d/dz [z^8] = 8z^7
det| 9 6 ; 6 10 | = 54
det| 8 7 ; 4 9 | = 44
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
9z² + 2z + 4 = 0
ΔS ≥ 0
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
\frac{10}{1} \sum_{i=1}^{n} i^{2}