Math Dump /sym/2cb7bd
id=187766 · host=jp.commstar.world · 2026-09-01 21:07Z
F = ma
det| 4 1 ; 6 5 | = 14
402K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 5 3 ; 7 6 | = 9
398K
∇²β = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
9φ² + 2φ + 4 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
det| 7 4 ; 0 8 | = 56
∫₀^∞ e^(-t²) dt = √π / 2
ω = 2πf
det| 1 1 ; 5 2 | = -3
2t² + 7t + 5 = 0