Math Dump /sym/7ea3ed
id=198777 · host=jp.commstar.world · 2026-09-01 21:08Z
∇²z = 0
det| 4 1 ; 6 5 | = 14
402K
det| 8 6 ; 7 9 | = 30
det| 5 3 ; 7 6 | = 9
398K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 7 ; 2 10 | = 76
9β² + 9β + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
ΔS ≥ 0
ΔS ≥ 0
3φ² + 3φ + 0 = 0
7t² + 6t + 4 = 0