Math Dump /sym/89e13b
id=204987 · host=jp.commstar.world · 2026-09-01 21:07Z
∇ × E = −∂B/∂t
det| 4 1 ; 6 5 | = 14
402K
1t² + 9t + 4 = 0
det| 5 3 ; 7 6 | = 9
398K
∇²β = 0
∇²θ = 0
6θ² + 4θ + 7 = 0
det| 3 6 ; 2 4 | = 0
e^{i\pi} + 1 = 0
det| 4 6 ; 5 5 | = -10
5φ² + 1φ + 0 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-φ²) dφ = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂