Math Dump /sym/25f476
id=229860 · host=jp.commstar.world · 2026-09-01 21:06Z
ΔS ≥ 0
det| 4 1 ; 6 5 | = 14
402K
6ω² + 7ω + 0 = 0
det| 5 3 ; 7 6 | = 9
398K
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{4}{5} \sum_{i=1}^{n} i^{2}
11t² + 8t + 4 = 0
det| 10 9 ; 7 11 | = 47
5n² + 7n + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p
det| 11 3 ; 1 12 | = 129
det| 3 1 ; 4 4 | = 8