Math Dump /sym/5c4922
id=24858 · host=jp.commstar.world · 2026-09-01 21:05Z
5n² + 4n + 7 = 0
det| 4 1 ; 6 5 | = 14
402K
∇²z = 0
det| 5 3 ; 7 6 | = 9
398K
e^{i\pi} + 1 = 0
det| 4 9 ; 4 5 | = -16
2H₂ + O₂ → 2H₂O
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
det| 3 8 ; 2 4 | = -4
\binom{n}{k} = \frac{n!}{k!(n-k)!}