Math Dump /sym/866687
id=25675 · host=jp.commstar.world · 2026-09-01 21:05Z
∇ × E = −∂B/∂t
det| 4 1 ; 6 5 | = 14
402K
det| 1 1 ; 6 2 | = -4
det| 5 3 ; 7 6 | = 9
398K
F = G m₁m₂ / r²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
7y² + 8y + 0 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
9x² + 6x + 0 = 0
det| 11 6 ; 4 12 | = 108
ΔS ≥ 0
ω = 2πf
det| 2 2 ; 2 3 | = 2
\oint_C \vec{F}\cdot d\vec{r} = 0