Math Dump /sym/68aa28
id=271661 · host=jp.commstar.world · 2026-09-01 21:08Z
3t² + 8t + 7 = 0
det| 4 1 ; 6 5 | = 14
402K
∑_{k=1}^{n} k = n(n+1)/2
det| 5 3 ; 7 6 | = 9
398K
7ω² + 4ω + 4 = 0
3r² + 8r + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
N₂ + 3H₂ ⇌ 2NH₃
CH₄ + 2O₂ → CO₂ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
4n² + 4n + 0 = 0