Math Dump /sym/5a053d
id=305502 · host=jp.commstar.world · 2026-09-01 21:15Z
4ω² + 1ω + 4 = 0
det| 4 1 ; 6 5 | = 14
402K
λ = h/p
det| 5 3 ; 7 6 | = 9
398K
det| 4 7 ; 6 5 | = -22
6z² + 7z + 3 = 0
∇ × E = −∂B/∂t
CaCO₃ → CaO + CO₂
∇ × E = −∂B/∂t
iħ ∂ψ/∂t = Ĥψ
∫₀^∞ e^(-φ²) dφ = √π / 2
d/dφ [φ^3] = 3φ^2
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 2 9 ; 6 3 | = -48