Math Dump /sym/e5f248
id=349279 · host=jp.commstar.world · 2026-09-01 21:07Z
det| 3 4 ; 7 4 | = -16
det| 4 1 ; 6 5 | = 14
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∫₀^∞ e^(-θ²) dθ = √π / 2
det| 5 3 ; 7 6 | = 9
398K
det| 12 4 ; 5 13 | = 136
4t² + 7t + 1 = 0
ω = 2πf
∇²ψ = 0
PV = nRT
CaCO₃ → CaO + CO₂
det| 2 5 ; 3 3 | = -9
5ω² + 8ω + 7 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
ω = 2πf