Math Dump /sym/2f6fbb
id=371042 · host=jp.commstar.world · 2026-09-01 21:08Z
det| 10 2 ; 4 11 | = 102
det| 4 1 ; 6 5 | = 14
402K
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 5 3 ; 7 6 | = 9
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
10t² + 2t + 5 = 0
E = mc²
∫₀^∞ e^(-y²) dy = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
d/dn [n^11] = 11n^10
∇ × E = −∂B/∂t
F = ma
det| 6 4 ; 0 7 | = 42
11n² + 7n + 7 = 0