Math Dump /sym/bcca34
id=379698 · host=jp.commstar.world · 2026-09-01 21:08Z
8r² + 3r + 6 = 0
det| 4 1 ; 6 5 | = 14
402K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 3 ; 7 6 | = 9
398K
5n² + 1n + 1 = 0
6ψ² + 8ψ + 3 = 0
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-t²) dt = √π / 2
∂t/∂θ = 1t
det| 3 4 ; 4 4 | = -4
det| 8 9 ; 4 9 | = 36
E = mc²
∑_{k=1}^{n} k = n(n+1)/2