Math Dump /sym/336b5a
id=389667 · host=jp.commstar.world · 2026-09-01 21:06Z
det| 11 3 ; 1 12 | = 129
det| 4 1 ; 6 5 | = 14
402K
∑_{k=1}^{n} k = n(n+1)/2
det| 5 3 ; 7 6 | = 9
398K
11ω² + 7ω + 1 = 0
det| 6 8 ; 5 7 | = 2
F = ma
PV = nRT
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
F = ma
PV = nRT
ω = 2πf
8φ² + 2φ + 3 = 0
9r² + 1r + 4 = 0