Math Dump /sym/414fd7
id=402557 · host=jp.commstar.world · 2026-09-01 21:11Z
∫₀^∞ e^(-α²) dα = √π / 2
det| 4 1 ; 6 5 | = 14
402K
det| 10 4 ; 3 11 | = 98
det| 5 3 ; 7 6 | = 9
398K
d/dt [t^1] = 1t^0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
5z² + 6z + 4 = 0
3β² + 7β + 7 = 0
7α² + 4α + 4 = 0
ΔS ≥ 0
d/dβ [β^10] = 10β^9
\frac{5}{6} \sum_{i=1}^{n} i^{2}
det| 4 8 ; 1 5 | = 12