Math Dump /sym/611b3f
id=411383 · host=jp.commstar.world · 2026-09-01 21:11Z
F = ma
det| 4 1 ; 6 5 | = 14
402K
e^{i\pi} + 1 = 0
det| 5 3 ; 7 6 | = 9
398K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∇²n = 0
e^{i\pi} + 1 = 0
\lim_{r\to 0} \frac{\sin r}{r} = 1
12t² + 4t + 3 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
Fe₂O₃ + 3CO → 2Fe + 3CO₂
N₂ + 3H₂ ⇌ 2NH₃
det| 11 3 ; 1 12 | = 129
det| 10 3 ; 2 11 | = 104