Math Dump /sym/60c108
id=429462 · host=jp.commstar.world · 2026-09-01 21:05Z
∇²φ = 0
det| 4 1 ; 6 5 | = 14
402K
7ω² + 5ω + 2 = 0
det| 5 3 ; 7 6 | = 9
398K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
PV = nRT
det| 12 2 ; 5 13 | = 146
3t² + 9t + 4 = 0
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 4 9 ; 4 5 | = -16
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
E = mc²
det| 3 7 ; 0 4 | = 12
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1