Math Dump /sym/130b8e
id=487672 · host=jp.commstar.world · 2026-09-01 21:05Z
2ψ² + 4ψ + 4 = 0
det| 4 1 ; 6 5 | = 14
402K
∫₀^∞ e^(-x²) dx = √π / 2
det| 5 3 ; 7 6 | = 9
398K
det| 6 4 ; 1 7 | = 38
\binom{n}{k} = \frac{n!}{k!(n-k)!}
ΔS ≥ 0
F = ma
∂x/∂n = 4x
∂ψ/∂r = 6ψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
ΔS ≥ 0
8θ² + 5θ + 0 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0