Math Dump /sym/b69c0e
id=508300 · host=jp.commstar.world · 2026-09-01 21:13Z
∇ × E = −∂B/∂t
det| 4 1 ; 6 5 | = 14
402K
8ψ² + 2ψ + 0 = 0
det| 5 3 ; 7 6 | = 9
398K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
e^{i\pi} + 1 = 0
e^{i\pi} + 1 = 0
6θ² + 1θ + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
CaCO₃ → CaO + CO₂
det| 4 6 ; 6 5 | = -16
e^{i\pi} + 1 = 0