Math Dump /sym/5e7128
id=555183 · host=jp.commstar.world · 2026-09-01 21:05Z
E = mc²
det| 4 1 ; 6 5 | = 14
402K
e^{i\pi} + 1 = 0
det| 5 3 ; 7 6 | = 9
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∇ × E = −∂B/∂t
E = mc²
2y² + 4y + 2 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
7φ² + 8φ + 2 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
∂φ/∂r = 1φ
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 3 9 ; 5 4 | = -33
\binom{n}{k} = \frac{n!}{k!(n-k)!}