Math Dump /sym/c592f4
id=566138 · host=jp.commstar.world · 2026-09-01 21:10Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 1 ; 6 5 | = 14
402K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 5 3 ; 7 6 | = 9
398K
∇²r = 0
∇ × E = −∂B/∂t
det| 1 2 ; 3 2 | = -4
3γ² + 1γ + 6 = 0
6t² + 4t + 1 = 0
det| 9 5 ; 6 10 | = 60
det| 11 5 ; 4 12 | = 112
3β² + 2β + 7 = 0
d/dβ [β^1] = 1β^0
∇²ω = 0