Math Dump /sym/3a8a47
id=573388 · host=jp.commstar.world · 2026-09-01 21:07Z
det| 2 9 ; 3 3 | = -21
det| 4 1 ; 6 5 | = 14
402K
λ = h/p
det| 5 3 ; 7 6 | = 9
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
4ω² + 4ω + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
F = ma
∫₀^∞ e^(-r²) dr = √π / 2
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 8 ; 6 9 | = 24
\binom{n}{k} = \frac{n!}{k!(n-k)!}
AgNO₃ + NaCl → AgCl↓ + NaNO₃
ΔS ≥ 0