Math Dump /sym/175db0
id=579786 · host=jp.commstar.world · 2026-09-01 21:13Z
ω = 2πf
det| 4 1 ; 6 5 | = 14
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det| 4 6 ; 5 5 | = -10
det| 5 3 ; 7 6 | = 9
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ΔS ≥ 0
∇²t = 0
6α² + 8α + 7 = 0
e^{i\pi} + 1 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 2 5 ; 4 3 | = -14
det| 6 8 ; 4 7 | = 10
∂β/∂ω = 6β
∂φ/∂ψ = 3φ