Math Dump /sym/bc0121
id=580633 · host=jp.commstar.world · 2026-09-01 21:07Z
det| 10 9 ; 6 11 | = 56
det| 4 1 ; 6 5 | = 14
402K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 5 3 ; 7 6 | = 9
398K
\lim_{n\to 0} \frac{\sin n}{n} = 1
det| 11 7 ; 0 12 | = 132
∇²x = 0
E = mc²
iħ ∂ψ/∂t = Ĥψ
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∂x/∂ψ = 7x
∫₀^∞ e^(-x²) dx = √π / 2
det| 9 1 ; 4 10 | = 86
11θ² + 3θ + 0 = 0