Math Dump /sym/420511
id=58369 · host=jp.commstar.world · 2026-09-01 21:05Z
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 4 1 ; 6 5 | = 14
402K
\frac{12}{8} \sum_{i=1}^{n} i^{2}
det| 5 3 ; 7 6 | = 9
398K
iħ ∂ψ/∂t = Ĥψ
ω = 2πf
2β² + 7β + 4 = 0
3ψ² + 4ψ + 3 = 0
1x² + 5x + 2 = 0
\frac{8}{4} \sum_{i=1}^{n} i^{2}
\lim_{β\to 0} \frac{\sin β}{β} = 1
12θ² + 6θ + 4 = 0
E = mc²
E = mc²