Math Dump /sym/282b26
id=635523 · host=jp.commstar.world · 2026-09-01 21:09Z
∫₀^∞ e^(-n²) dn = √π / 2
det| 4 1 ; 6 5 | = 14
402K
8n² + 3n + 3 = 0
det| 5 3 ; 7 6 | = 9
398K
ω = 2πf
2H₂ + O₂ → 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
2ψ² + 9ψ + 6 = 0
1r² + 4r + 7 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
ΔS ≥ 0
ω = 2πf