Math Dump /sym/0637a0
id=639649 · host=jp.commstar.world · 2026-09-01 21:11Z
10φ² + 5φ + 3 = 0
det| 4 1 ; 6 5 | = 14
402K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 5 3 ; 7 6 | = 9
398K
det| 5 1 ; 6 6 | = 24
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-γ²) dγ = √π / 2
∇ × E = −∂B/∂t
det| 5 8 ; 7 6 | = -26
\frac{3}{5} \sum_{i=1}^{n} i^{2}
ΔS ≥ 0
λ = h/p