Math Dump /sym/8c7a4f
id=657727 · host=jp.commstar.world · 2026-09-01 21:08Z
F = ma
det| 4 1 ; 6 5 | = 14
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\frac{10}{3} \sum_{i=1}^{n} i^{2}
det| 5 3 ; 7 6 | = 9
398K
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\lim_{n\to 0} \frac{\sin n}{n} = 1
11α² + 2α + 4 = 0
3φ² + 9φ + 1 = 0
det| 1 6 ; 0 2 | = 2
det| 3 9 ; 4 4 | = -24
\lim_{z\to 0} \frac{\sin z}{z} = 1
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2