Math Dump /sym/901975
id=673476 · host=jp.commstar.world · 2026-09-01 21:06Z
12ψ² + 9ψ + 4 = 0
det| 4 1 ; 6 5 | = 14
402K
E = mc²
det| 5 3 ; 7 6 | = 9
398K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 3 7 ; 3 4 | = -9
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
CaCO₃ → CaO + CO₂
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
∇ × E = −∂B/∂t
12y² + 8y + 3 = 0
9ω² + 8ω + 5 = 0