Math Dump /sym/721ea0
id=729003 · host=jp.commstar.world · 2026-09-01 21:06Z
E = mc²
det| 4 1 ; 6 5 | = 14
402K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 5 3 ; 7 6 | = 9
398K
CH₄ + 2O₂ → CO₂ + 2H₂O
∇ × E = −∂B/∂t
10n² + 8n + 6 = 0
det| 8 8 ; 7 9 | = 16
4θ² + 2θ + 0 = 0
\frac{1}{3} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
ΔS ≥ 0
\frac{12}{1} \sum_{i=1}^{n} i^{2}
8ω² + 6ω + 5 = 0