Math Dump /sym/3c27b0
id=77612 · host=jp.commstar.world · 2026-09-01 21:05Z
det| 4 7 ; 3 5 | = -1
det| 4 1 ; 6 5 | = 14
402K
E = mc²
det| 5 3 ; 7 6 | = 9
398K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 4 3 ; 3 5 | = 11
∇²x = 0
E = mc²
E = mc²
ΔS ≥ 0
d/dt [t^11] = 11t^10
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 3 5 ; 6 4 | = -18
det| 1 4 ; 3 2 | = -10