Math Dump /sym/4372cc
id=806336 · host=jp.commstar.world · 2026-09-01 21:07Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 1 ; 6 5 | = 14
402K
6θ² + 8θ + 1 = 0
det| 5 3 ; 7 6 | = 9
398K
∑_{k=1}^{n} k = n(n+1)/2
∇²φ = 0
8z² + 1z + 0 = 0
9y² + 3y + 1 = 0
det| 3 6 ; 7 4 | = -30
det| 9 6 ; 4 10 | = 66
d/dn [n^3] = 3n^2
∂x/∂ω = 3x
11ψ² + 1ψ + 4 = 0
det| 11 3 ; 3 12 | = 123