Math Dump /sym/9633b1
id=845995 · host=jp.commstar.world · 2026-09-01 21:08Z
2H₂ + O₂ → 2H₂O
det| 4 1 ; 6 5 | = 14
402K
2t² + 1t + 2 = 0
det| 5 3 ; 7 6 | = 9
398K
ΔS ≥ 0
N₂ + 3H₂ ⇌ 2NH₃
det| 3 2 ; 6 4 | = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 3 8 ; 5 4 | = -28
8ω² + 9ω + 7 = 0
e^{i\pi} + 1 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2