Math Dump /sym/b5bc67
id=860044 · host=jp.commstar.world · 2026-09-01 21:06Z
F = ma
det| 4 1 ; 6 5 | = 14
402K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 5 3 ; 7 6 | = 9
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
N₂ + 3H₂ ⇌ 2NH₃
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 2 9 ; 1 3 | = -3
d/dφ [φ^10] = 10φ^9
∇ × E = −∂B/∂t
\lim_{x\to 0} \frac{\sin x}{x} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0