Math Dump /sym/bfc685
id=863282 · host=jp.commstar.world · 2026-09-01 21:05Z
det| 2 5 ; 6 3 | = -24
det| 4 1 ; 6 5 | = 14
402K
N₂ + 3H₂ ⇌ 2NH₃
det| 5 3 ; 7 6 | = 9
398K
12β² + 4β + 0 = 0
det| 6 6 ; 7 7 | = 0
∑_{k=1}^{n} k = n(n+1)/2
∂ψ/∂z = 5ψ
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
det| 12 5 ; 0 13 | = 156
e^{i\pi} + 1 = 0
E = mc²
PV = nRT