Math Dump /sym/d06ef8
id=86665 · host=jp.commstar.world · 2026-09-01 21:05Z
det| 4 2 ; 5 5 | = 10
det| 4 1 ; 6 5 | = 14
402K
∫₀^∞ e^(-n²) dn = √π / 2
det| 5 3 ; 7 6 | = 9
398K
10γ² + 2γ + 3 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
PV = nRT
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∇²z = 0
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 1 3 ; 4 2 | = -10
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O