Math Dump /sym/c99b3f
id=88398 · host=jp.commstar.world · 2026-09-01 21:05Z
\frac{9}{5} \sum_{i=1}^{n} i^{2}
det| 4 1 ; 6 5 | = 14
402K
CaCO₃ → CaO + CO₂
det| 5 3 ; 7 6 | = 9
398K
det| 4 8 ; 1 5 | = 12
det| 11 5 ; 5 12 | = 107
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
ΔS ≥ 0
CH₄ + 2O₂ → CO₂ + 2H₂O
\lim_{r\to 0} \frac{\sin r}{r} = 1
4ω² + 9ω + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∂β/∂x = 3β