Math Dump /sym/ca4718
id=949012 · host=jp.commstar.world · 2026-09-01 21:05Z
PV = nRT
det| 4 1 ; 6 5 | = 14
402K
det| 5 7 ; 6 6 | = -12
det| 5 3 ; 7 6 | = 9
398K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
ΔS ≥ 0
1θ² + 7θ + 4 = 0
det| 1 1 ; 4 2 | = -2
\lim_{z\to 0} \frac{\sin z}{z} = 1
det| 3 3 ; 0 4 | = 12
4β² + 3β + 4 = 0
\lim_{n\to 0} \frac{\sin n}{n} = 1
∑_{k=1}^{n} k = n(n+1)/2
N₂ + 3H₂ ⇌ 2NH₃