Math Dump /sym/185bb8
id=965550 · host=jp.commstar.world · 2026-09-01 21:07Z
∫₀^∞ e^(-n²) dn = √π / 2
det| 4 1 ; 6 5 | = 14
402K
det| 1 6 ; 3 2 | = -16
det| 5 3 ; 7 6 | = 9
398K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∂β/∂φ = 1β
det| 11 3 ; 4 12 | = 120
1ψ² + 9ψ + 0 = 0
det| 12 6 ; 7 13 | = 114
12n² + 3n + 7 = 0
\frac{12}{9} \sum_{i=1}^{n} i^{2}
det| 2 3 ; 5 3 | = -9
N₂ + 3H₂ ⇌ 2NH₃
E = mc²