Math Dump /sym/998052
id=989148 · host=jp.commstar.world · 2026-09-01 21:05Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 1 ; 6 5 | = 14
402K
10t² + 1t + 6 = 0
det| 5 3 ; 7 6 | = 9
398K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
6γ² + 5γ + 3 = 0
7ω² + 3ω + 6 = 0
7β² + 2β + 2 = 0
det| 7 9 ; 5 8 | = 11
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{y\to 0} \frac{\sin y}{y} = 1
\lim_{n\to 0} \frac{\sin n}{n} = 1